Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH (C₁₇H₃₅COOH) ₂ ΔH°_rxn = -172 kJ
The equilibrium constant for this reaction at 28°C is 2900. Estimate the equilibrium constant at 38°C.

Question

Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH

Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C<sub>17</sub>H<sub>35</sub>COOH (C<sub>17</sub>H<sub>35</sub>COOH) <sub>2</sub> ΔH°<sub>rxn</sub> = -172 kJ The equilibrium constant for this reaction at 28°C is 2900. Estimate the equilibrium constant at 38°C. A) 4.7 × 10<sup>5</sup> B) 2.6 × 10<sup>4</sup> C) 1.9 × 10<sup>3</sup> D) 3.2 × 10<sup>2</sup> E) 18

(C₁₇H₃₅COOH) ₂ ΔH°_rxn = -172 kJ
The equilibrium constant for this reaction at 28°C is 2900. Estimate the equilibrium constant at 38°C.

Quizplus · Accepted Answer

The Answer of Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH (C₁₇H₃₅COOH)₂ ΔH°_rxn = -172 kJ The equilibrium constant for this reaction at 28°C is 2900. Estimate the equilibrium constant at 38°C.

Stearic Acid, Nature's Most Common Fatty Acid, Dimerizes When Dissolved