A 32-bit logical address with 8 KB page size will have 1,000,000 entries in a conventional page table.

Question

Quizplus · Accepted Answer

In a conventional paging system, the page table entry stores the physical frame number of the corresponding page. Assuming a 32-bit logical address space, and an 8 KB (2^13) page size, the page offset will be 13 bits (the number of bits required to represent 8 KB). Therefore, the remaining 19 bits will be used to index the page table. With a conventional approach, where each entry in the page table typically requires 4 bytes (32 bits) and assuming a page table containing only mappings for the 32-bit logical address space, the page table will have 2^19 entries. Hence, the correct answer is option B.

A 32-Bit Logical Address with 8 KB Page Size Will