Calculate the 99% confidence interval for a sample of N = 19 with a mean 
= 27.18 and standard deviation (s) = 10.31.
A) 99% CI = 27.18 ± 4.98
B) 99% CI = 27.18 ± 4.11
C) 99% CI = 27.18 ± 6.82
D) 99% CI = 27.18 ± 5.25
Correct Answer:
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