Write a balanced half-reaction for the reduction of CrO42-(aq) to Cr(OH) 3(s) in a basic solution.
A) CrO42-(aq) + 3 OH-(aq) + 3 e- → Cr(OH) 3(s) + 2 O2(g)
B) CrO42-(aq) + 3 H+(aq) + 3 e- → Cr(OH) 3(s)
C) CrO42-(aq) + 3 H+(aq) → Cr(OH) 3(s) + 2 e-
D) CrO42-(aq) + 4 H2O( ) + 3 e- → Cr(OH) 3(s) + 5 OH-(aq)
E) CrO42-(aq) + 3 OH-(aq) → Cr(OH) 3(s) + 2 O2(g)
Correct Answer:
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