Calculate the charge,in coulombs,is required to deposit 1.5 g of solid magnesium from a solution of Mg²⁺(aq)ion. A) 4.1 × 10² C B) 6.0 × 10³ C C) 1.2 × 10⁴ C D) 2.9 × 10⁵ C E) 3.1 × 10⁶ C

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Quizplus · Accepted Answer

To deposit 1.5 g of Mg, calculate moles of Mg: 1.5 g / 24.305 g/mol = 0.0617 mol. Mg^2+ requires 2 moles of electrons per mole of Mg, so 0.0617 mol × 2 = 0.1234 mol of electrons. Using Faraday's constant (96485 C/mol), the charge is 0.1234 mol × 96485 C/mol = 1.2 × 10^4 C.

Calculate the Charge,in Coulombs,is Required to Deposit 1