Calculate the pH of a solution made by mixing 100.0 mL of 0.627 M NH₃ with 100.0 mL of 0.100 M HCl.(K_b for NH₃ = 1.8 × 10^-5) A) 9.98 B) 4.02 C) 8.53 D) 9.26 E) none of these

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Quizplus · Accepted Answer

The reaction between NH3 and HCl is a neutralization reaction. The products of the reaction are NH4Cl and water. The pH of the solution can be calculated using the following equation:pH = -log[H+],where [H+] is the molar concentration of hydrogen ions in the solution.The molar concentration of hydrogen ions can be calculated using the following equation:[H+] = Kw/[OH-],where Kw is the ion product constant for water (1.0 x 10^-14) and [OH-] is the molar concentration of hydroxide ions in the solution.The molar concentration of hydroxide ions can be calculated using the following equation:[OH-] = Kb[NH3]/[NH4+],where Kb is the base dissociation constant for NH3 (1.8 x 10^-5) and [NH3] and [NH4+] are the molar concentrations of NH3 and NH4+, respectively.The molar concentrations of NH3 and NH4+ can be calculated using the following equations:[NH3] = (0.627 M)(100.0 mL/200.0 mL) = 0.3135 M,[NH4+] = (0.100 M)(100.0 mL/200.0 mL) = 0.0500 M.Substituting these values into the equations above, we get:[OH-] = (1.8 x 10^-5)(0.3135 M)/(0.0500 M) = 1.10 x 10^-4 M,[H+] = (1.0 x 10^-14)/(1.10 x 10^-4 M) = 9.09 x 10^-11 M,pH = -log(9.09 x 10^-11 M) = 9.98.Therefore, the pH of the solution is 9.98.

Calculate the PH of a Solution Made by Mixing 100