What is the pOH of 0.074 M HI(aq)at 25 °C? (K_w = 1.01 × 10^-14)?

Name: What is the pOH of 0.074 M HI(aq)at 25 °C? (K w = 1.01 × 10 -14 )?
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Quizplus · Accepted Answer

The pOH of a solution can be found using the formula pOH = 14 - pH. Since HI is a strong acid, it dissociates completely in water, meaning the concentration of H+ ions is equal to the initial concentration of HI, which is 0.074 M. The pH is calculated using the formula pH = -log[H+], which gives pH = -log(0.074) ≈ 1.13. Therefore, pOH = 14 - 1.13 = 12.87.

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