What is the pH of a solution prepared by dissolving 0.459 L of HCl(g),measured at STP,in enough water such that the total volume of the solution is 5.50 L? (R = 0.0821 L · atm/K·mol)
A) 2.429
B) 11.571
C) 1.689
D) 7.000
E) 12.311

Question

Quizplus · Accepted Answer

The correct answer is A because the pH of a solution is determined by the concentration of hydrogen ions (H+). The concentration of H+ ions in a solution can be calculated using the following equation:[H+] = M * V / RTwhere:[H+] is the concentration of hydrogen ions in moles per literM is the molarity of the solution in moles per literV is the volume of the solution in litersR is the ideal gas constant (0.0821 L · atm/K·mol)T is the temperature in KelvinIn this problem, we are given the following information:V = 5.50 LT = 273 K (STP)R = 0.0821 L · atm/K·molM = 0.459 L / 5.50 L = 0.0835 MPlugging these values into the equation, we get:[H+] = 0.0835 M * 5.50 L / 0.0821 L · atm/K·mol * 273 K = 1.00 x 10^-2 MThe pH of a solution is defined as the negative logarithm of the hydrogen ion concentration:pH = -log[H+]Plugging in the value of [H+], we get:pH = -log(1.00 x 10^-2) = 2.429Therefore, the pH of the solution is 2.429.

What Is the PH of a Solution Prepared by Dissolving