What is the equilibrium pH of a 0.700 M solution of H₃PO₄(aq)? (K_a1 = 7.5 × 10^-3,K_a2 = 6.2 × 10^-8,K_a3 = 4.8 × 10^-13) A) 1.16 B) 3.68 C) 12.32 D) 6.24 E) 7.21

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Quizplus · Accepted Answer

The first dissociation constant (Ka1) is the most significant for determining the pH of a strong acid like H3PO4. Using Ka1, the pH is calculated as -log(sqrt(Ka1 * [H3PO4])) which gives approximately 1.16.

What Is the Equilibrium PH of a 0