The solubility of 1-pentanol in water is 2.7 g per 100 g of water at 25°C.What is the maximum amount of 1-pentanol that will dissolve in 2.1 g of water at 25°C?
A) 0.057 g
B) 1.3 g
C) 2.7 g
D) 5.7 g
E) 0.013 g

Question

Quizplus · Accepted Answer

The solubility of 1-pentanol in water is given as 2.7 g per 100 g of water. To find the amount that will dissolve in 2.1 g of water, use a proportion: (2.7 g / 100 g water) = (x g / 2.1 g water). Solving for x gives x = (2.7 * 2.1) / 100 = 0.0567 g, which rounds to 0.057 g.

The Solubility of 1-Pentanol in Water Is 2