Ammonia gas is synthesized according to the balanced equation below. N₂(g) + 3 H₂(g) → 2 NH₃(g)
If 1.55 L N₂ react with 4.92 L H₂,what is the theoretical yield (in liters) of NH₃? Assume that the volumes of reactants and products are measured at the same temperature and pressure.

Question

Quizplus · Accepted Answer

The balanced equation shows that 1 mole of $N_2$ reacts with 3 moles of $H_2$ to produce 2 moles of $NH_3$. Since the reaction involves gases at the same temperature and pressure, we can use volumes directly in the mole ratio. $N_2$ is the limiting reactant because $1.55 L$ of $N_2$ would require $3 \times 1.55 = 4.65 L$ of $H_2$, but there is more $H_2$ available. Therefore, $1.55 L$ of $N_2$ would produce $2 \times 1.55 = 3.10 L$ of $NH_3$, making the theoretical yield $3.10 L$.

Ammonia Gas Is Synthesized According to the Balanced Equation Below