The heat of vaporization of benzene,C₆H₆,is 30.7 kJ/mol at its boiling point of 80.1 °C.How much energy in the form of heat is required to vaporize 102 g benzene at its boiling point?

Question

Quizplus · Accepted Answer

To find the energy required, first calculate the number of moles of benzene: 102 g / 78.11 g/mol = 1.306 moles. Then multiply by the heat of vaporization: 1.306 moles × 30.7 kJ/mol = 40.1 kJ.

The Heat of Vaporization of Benzene,C6H6,is 30

The Heat of Vaporization of Benzene,C₆H₆,is 30