How many moles of sodium bromide can be produced from the reaction of 1.03 moles of sodium with 0.650 moles of bromine gas? 2 Na(s) + Br2(g) → 2 NaBr(s)
A) 0.650 mol
B) 1.03 mol
C) 1.30 mol
D) 2.06 mol
E) 0.515 mol
Correct Answer:
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