How many moles of Mg₃P₂(s)can be produced from the reaction of 0.14 mol Mg(s)with 0.020 mol P₄(s)? 6 Mg(s)+ P₄(s)→ 2 Mg₃P₂(s)

Question

Quizplus · Accepted Answer

The limiting reagent determines the amount of product formed. Here, 0.020 mol of $\text{P}_4\text{S}_{10}$ reacts with 6 times less Mg, meaning 0.020 mol of $\text{P}_4\text{S}_{10}$ can produce 2 times 0.020 mol of $\text{Mg}_3\text{P}_2\text{S}_{12}$, which is 0.040 mol.

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