If 56.0 g of O₂ is mixed with 56.0 g of H₂ and the mixture is ignited,what is the maximum mass of water that may be produced?

Question

Quizplus · Accepted Answer

The chemical formulas for the substances given in subscript notation are O2 and H2, indicating oxygen and hydrogen gases, respectively. The balanced chemical equation for the reaction between hydrogen and oxygen to form water is 2H2 + O2 → 2H2O. From the given masses (56.0 g of each gas), and using the molar masses (O2 = 32.0 g/mol, H2 = 2.02 g/mol), we can determine the limiting reactant and calculate the maximum mass of water produced. Hydrogen is the limiting reactant, and the theoretical yield of water is 63.0 g, based on stoichiometry and the molar mass of water (H2O = 18.02 g/mol).

If 560 G of O2 Is Mixed with 56

If 560 G of O₂ Is Mixed with 56