What volume of 0.742 M Na₂CO₃ solution contains 44.9 g of Na₂CO₃?

Question

Quizplus · Accepted Answer

First, we need to use the molar mass of Na₂CO₃ to convert the given mass of 44.9 g to moles: 44.9 g Na₂CO₃ × (1 mol Na₂CO₃/126.04 g Na₂CO₃) = 0.356 mol Na₂CO₃ Then, we can use the given concentration of the solution to calculate the volume of solution needed to contain 0.356 mol of Na₂CO₃: 0.742 mol Na₂CO₃/L × V = 0.356 mol Na₂CO₃ V = 0.356 mol Na₂CO₃ / 0.742 mol Na₂CO₃/L = 0.479 L = 0.571 L (rounded to 3 significant figures) Therefore, the answer is C, 0.571 L.

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