Which of the following is the correct mass percent of each element in sulfuric acid,H₂SO₄? A) 2.055% H,32.69% S,and 65.25% O B) 1.028% H,32.69% S,and 66.28% O C) 28.57% H,14.29% S,and 57.17% O D) 1.028% H,33.72% S,and 65.25% O E) 2.016% H,32.07% S,and 65.91% O

Question

Quizplus · Accepted Answer

To find the mass percent of each element, we need to first calculate the molar mass of sulfuric acid.

Molar mass of H = 1.0079 g/mol 
Molar mass of S = 32.065 g/mol 
Molar mass of O = 15.999 g/mol

Molar mass of sulfuric acid = (1 x 1.0079) + (1 x 32.065) + (4 x 15.999) = 98.079 g/mol

Now, we can calculate the mass percent of each element:

Mass percent of H = (2.0158 g/mol / 98.079 g/mol) x 100% = 2.055% 
Mass percent of S = (32.065 g/mol / 98.079 g/mol) x 100% = 32.69% 
Mass percent of O = (63.9972 g/mol / 98.079 g/mol) x 100% = 65.25%

Therefore, the correct answer is A.

Which of the Following Is the Correct Mass Percent of Each