Suppose Ingredient I is made up of 80% micoden and 20% water, Ingredient II is made up of 30% micoden, 50% bixon, and 20% water, and these ingredients are mixed together. How much micoden is in the mixture? INGREDIENT I
INGREDIENT II
MIXTURE
2 lb
11 lb
13 lb

A) 1.6 lb
B) 4.9 lb
C) 2.2 lb
D) 13 lb
E) 3.3 lb

Question

Suppose Ingredient I is made up of 80% micoden and 20% water, Ingredient II is made up of 30% micoden, 50% bixon, and 20% water, and these ingredients are mixed together. How much micoden is in the mixture? INGREDIENT I
INGREDIENT II
MIXTURE
2 lb
11 lb
13 lb
​
A) 1.6 lb
B) 4.9 lb
C) 2.2 lb
D) 13 lb
E) 3.3 lb

Quizplus · Accepted Answer

To find the amount of micoden in the mixture, calculate the amount of micoden in each ingredient and then sum them up. For Ingredient I (2 lb), 80% of 2 lb is micoden, which equals 1.6 lb. For Ingredient II (11 lb), 30% of 11 lb is micoden, which equals 3.3 lb. Adding these amounts gives 1.6 lb + 3.3 lb = 4.9 lb of micoden in the mixture.

Suppose Ingredient I Is Made Up of 80% Micoden and 20