Assuming independent assortment for all gene pairs, what is the probability that the following parents, AABbCc
× AaBbCc, will produce an AaBbCc offspring?

Question

Quizplus · Accepted Answer

For each gene pair, there are two possible alleles. The probability of getting the desired AaBbCc genotype from each pair is 1/4 (1/2 chance of getting Aa and 1/2 chance of getting Bb and 1/2 chance of getting Cc). To get the overall probability, we need to multiply the individual probabilities for each pair. There are three gene pairs, so the overall probability is (1/4) x (1/4) x (1/4) = 1/64. However, there are two ways to arrange the alleles to get the desired genotype (AaBbCc and aAbBcC), so we need to double the probability to get 1/32 or simplified to 1/8.

Assuming Independent Assortment for All Gene Pairs, What Is the Probability