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TABLE 11-3 a Realtor Wants to Compare the Average Sales-To-Appraisal Ratios of Ratios

Question 31

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TABLE 11-3
A realtor wants to compare the average sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D) . Four properties are randomly selected from each neighborhood and the ratios recorded for each, as shown below.
TABLE 11-3 A realtor wants to compare the average sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D) . Four properties are randomly selected from each neighborhood and the ratios recorded for each, as shown below. Interpret the results of the analysis summarized in the following table: A) 3. B) 4. C) 12. D) 16. Answer: A Diff: 1 -Referring to Table 11-3, the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub> = μ<sub>C</sub> = μ<sub>D</sub> B) H<sub>0</sub> : M<sub>A</sub> = M<sub>B</sub> = M<sub>C</sub> = M<sub>D</sub> C) H<sub>0</sub> : σ<sub>A</sub><sup>2</sup> = σ<sub>B</sub><sup>2</sup> = σ<sub>C</sub><sup>2</sup> = σ<sub>D</sub><sup>2</sup> D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B</sub> = π<sub>C</sub> = π<sub>D</sub> Interpret the results of the analysis summarized in the following table:
TABLE 11-3 A realtor wants to compare the average sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D) . Four properties are randomly selected from each neighborhood and the ratios recorded for each, as shown below. Interpret the results of the analysis summarized in the following table: A) 3. B) 4. C) 12. D) 16. Answer: A Diff: 1 -Referring to Table 11-3, the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub> = μ<sub>C</sub> = μ<sub>D</sub> B) H<sub>0</sub> : M<sub>A</sub> = M<sub>B</sub> = M<sub>C</sub> = M<sub>D</sub> C) H<sub>0</sub> : σ<sub>A</sub><sup>2</sup> = σ<sub>B</sub><sup>2</sup> = σ<sub>C</sub><sup>2</sup> = σ<sub>D</sub><sup>2</sup> D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B</sub> = π<sub>C</sub> = π<sub>D</sub> A) 3.
B) 4.
C) 12.
D) 16.
Answer:
A
Diff: 1
-Referring to Table 11-3, the null hypothesis for Levene's test for homogeneity of variances is


A) H0 : μA = μB = μC = μD
B) H0 : MA = MB = MC = MD
C) H0 : σA2 = σB2 = σC2 = σD2
D) H0 : πA = πB = πC = πD

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