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TABLE 11-8 A Hotel Chain Has Identically Sized Resorts in 5 Locations

Question 113

Multiple Choice

TABLE 11-8
A hotel chain has identically sized resorts in 5 locations. The data that follow resulted from analyzing the hotel occupancies on randomly selected days in the 5 locations.
TABLE 11-8 A hotel chain has identically sized resorts in 5 locations. The data that follow resulted from analyzing the hotel occupancies on randomly selected days in the 5 locations. Analysis of Variance Total -Referring to Table 11-8, the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub> = μ<sub>C</sub> = μ<sub>D</sub> B) H<sub>0</sub> : M<sub>A</sub> = M<sub>B</sub> = M<sub>C</sub> = M<sub>D</sub> C) H<sub>0</sub> : σ<sub>A</sub><sup>2</sup> = σ<sub>B</sub><sup>2</sup> = σ<sub>C</sub><sup>2</sup> = σ<sub>D</sub><sup>2</sup> D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B</sub> = π<sub>C</sub> = π<sub>D</sub> Analysis of Variance
TABLE 11-8 A hotel chain has identically sized resorts in 5 locations. The data that follow resulted from analyzing the hotel occupancies on randomly selected days in the 5 locations. Analysis of Variance Total -Referring to Table 11-8, the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub> = μ<sub>C</sub> = μ<sub>D</sub> B) H<sub>0</sub> : M<sub>A</sub> = M<sub>B</sub> = M<sub>C</sub> = M<sub>D</sub> C) H<sub>0</sub> : σ<sub>A</sub><sup>2</sup> = σ<sub>B</sub><sup>2</sup> = σ<sub>C</sub><sup>2</sup> = σ<sub>D</sub><sup>2</sup> D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B</sub> = π<sub>C</sub> = π<sub>D</sub> Total
-Referring to Table 11-8, the null hypothesis for Levene's test for homogeneity of variances is


A) H0 : μA = μB = μC = μD
B) H0 : MA = MB = MC = MD
C) H0 : σA2 = σB2 = σC2 = σD2
D) H0 : πA = πB = πC = πD

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