TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Table 9-6, suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650. What would be the p-value of this one-tail test?
A) 0.040
B) 0.160
C) 0.840
D) 0.960

Question

Quizplus · Accepted Answer

For a one-tail test, the p-value is half of the two-tail test p-value. Since the two-tail p-value is 0.080, the one-tail p-value is 0.040.

TABLE 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested