If you were constructing a 99% confidence interval of the population mean based on a sample of n=25 where the standard deviation of the sample s = 0.05, the critical value of t will be
A) 2.7969.
B) 2.7874.
C) 2.4922.
D) 2.4851.

Question

Quizplus · Accepted Answer

For a 99% confidence interval with a sample size of n=25, the degrees of freedom is 24 (n-1). The critical t-value for 24 degrees of freedom at a 99% confidence level is approximately 2.7969.

If You Were Constructing a 99% Confidence Interval of the Population