Given the following cross between parents of the genotypes AABBCc × AabbCc,assume complete dominance for each trait and independent assortment.What proportion of the progeny will be expected to phenotypically resemble the first parent?

Question

Quizplus · Accepted Answer

To determine the proportion of progeny that phenotypically resemble the first parent, we need to look at the traits that make up the phenotype of the first parent: A, B, and c. We know that the first parent is homozygous for A and B, and heterozygous for c. Therefore, all of its gametes will carry the dominant alleles A and B and half of its gametes will carry the recessive allele c.

When we cross this parent with the second parent, we can use a Punnett square to determine the possible genotypes of the progeny:

|   | A  | A  | B  | B  | c  | c  |
|---|---|---|---|---|---|---|
| A | AA | AA | AB | AB | Ac | Ac |
| a | Aa | Aa | Ab | Ab | ac | ac |

From this Punnett square, we can see that 3/4 of the progeny will have the dominant A and/or B traits that resemble the first parent. Therefore, the answer is C.

Given the Following Cross Between Parents of the Genotypes AABBCc