Figure 5.2
-The solutions in the two arms of the U-tube shown in Figure 5.2 are separated by a membrane that is permeable to water and glucose but not to sucrose.Side A is half-filled with a solution of 2 M sucrose and 1 M glucose.Side B is half-filled with 1 M sucrose and 2 M glucose.Initially,the liquid levels are equal.After the system depicted in the figure reaches equilibrium,what changes are observed with respect to the concentrations of sugars?

Question

Quizplus · Accepted Answer

Since both water and glucose can freely move across the membrane, they will equilibrate until the concentration is equal on both sides of the U-tube. This means that the concentration of glucose will be 1.5 M on both sides, and the concentration of sucrose will also equalize to 1.5 M on both sides. Therefore, the concentrations of glucose and sucrose will be equal in sides A and B.

Figure 5.2 -The Solutions in the Two Arms of the U-Tube Shown