What is the pH of a 0. 500 mol L^-1 NH₃ solution that has K_b = 1.8 × 10^-5? The equation for the dissociation of NH₃ is below: NH₃(aq)+H₂O(l) ⇌NH₄+(aq)+OH-(aq) A) 2.22 B) 2. 52 C) 11. 48 D) 10.48

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The Answer of What is the pH of a 0. 500 mol L^-1 NH₃ solution that has K_b = 1.8 × 10^-5? The equation for the dissociation of NH₃ is below: NH₃(aq)+H₂O(l) ⇌NH₄+(aq)+OH-(aq) A) 2.22 B) 2. 52 C) 11. 48 D) 10.48

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