The reaction below has a K_p value of 3.3 × 10^-5bar. What is the value of K_c for this reaction at 700 K? 2SO₃(g) ⇌ 2SO₂(g) + O₂(g)

Name: The reaction below has a K p value of 3.3 × 10 -5 bar. What is the value of K c for this reaction at 700 K? 2SO 3 (g) ⇌ 2SO 2 (g) + O 2 (g)
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Quizplus · Accepted Answer

The correct answer is A because Kp = Kc(RT)^Δn, where Δn is the change in the number of moles of gas. In this case, Δn = 1, so Kc = Kp/(RT) = (3.3 × 10^-5 bar)/(0.08314 bar L/(mol K) * 700 K) = 5.7 × 10^-7 M.

The Reaction Below Has a Kp Value of 3

The Reaction Below Has a K_p Value of 3