The for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g) + (g) → (g)
In an equilibrium mixture of the three gases, = = 1.92 × 10^-4 bar. The partial pressure of the product, phosgene ( ) , is ________ bar.

Question

The

The for the reaction below is 1.49 × 10<sup>8</sup> bar<sup>-1</sup> at 100.0 °C: CO(g) + (g) → (g) In an equilibrium mixture of the three gases, = = 1.92 × 10<sup>-4</sup> bar. The partial pressure of the product, phosgene ( ) , is ________ bar. A) 5.49 B) 4.04 × 10<sup>15</sup> C) 2.86 × 10<sup>4</sup> D) 7.76 × 10<sup>11</sup> E) 2.47 × 10<sup>-16</sup>

for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g) + The for the reaction below is 1.49 × 108 bar-1 at 100.0 °C: CO(g) + (g) → (g) In an equilibrium mixture of the three gases, = = 1.92 × 10-4 bar. The partial pressure of the product, phosgene ( ) , is ________ bar. A) 5.49 B) 4.04 × 1015 C) 2.86 × 104 D) 7.76 × 1011 E) 2.47 × 10-16

(g) →

(g)
In an equilibrium mixture of the three gases, The for the reaction below is 1.49 × 108 bar-1 at 100.0 °C: CO(g) + (g) → (g) In an equilibrium mixture of the three gases, = = 1.92 × 10-4 bar. The partial pressure of the product, phosgene ( ) , is ________ bar. A) 5.49 B) 4.04 × 1015 C) 2.86 × 104 D) 7.76 × 1011 E) 2.47 × 10-16

=

= 1.92 × 10^-4 bar. The partial pressure of the product, phosgene ( The for the reaction below is 1.49 × 108 bar-1 at 100.0 °C: CO(g) + (g) → (g) In an equilibrium mixture of the three gases, = = 1.92 × 10-4 bar. The partial pressure of the product, phosgene ( ) , is ________ bar. A) 5.49 B) 4.04 × 1015 C) 2.86 × 104 D) 7.76 × 1011 E) 2.47 × 10-16

) , is ________ bar.

Quizplus · Accepted Answer

The Answer of The for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g) + (g) → (g) In an equilibrium mixture of the three gases, = = 1.92 × 10^-4 bar. The partial pressure of the product, phosgene ( ), is ________ bar.

The for the Reaction Below Is 1