For a reaction that follows the general rate law Rate = k[A]^1/2[B]², what will happen to the rate of reaction if the concentration of A and B are is increased by a factor of 4?

Question

Quizplus · Accepted Answer

The rate of reaction is proportional to [A]^1/2[B]². If we increase the concentration of A and B by a factor of 4, then the new concentration would be 4[A] and 4[B]. Plugging this into the rate law, we get: Rate = k[4A]^1/2[4B]² = k(4^1/2)(4²)[A]^1/2[B]² = 16k[A]^1/2[B]² Therefore, the rate of the reaction will increase by a factor of 16 (Choice C).

For a Reaction That Follows the General Rate Law Rate