For a reaction that follows the general rate law Rate = k[A]⁰[B][C]², what will happen to the rate of reaction if the concentration of A is increased by a factor of 4, the concentration of B is increased by a factor of 2, and the concentration of C is increased by a factor 6?

Question

Quizplus · Accepted Answer

The rate law shows that the rate is directly proportional to [A]^S1U1P10 and [B]^S1U1P12, and also proportional to [C]^S1U1P12. Therefore, increasing the concentration of A by a factor of 4 will increase the rate by 4^1U1P10=4. Increasing the concentration of B by a factor of 2 will increase the rate by 2^1U1P12=2. Increasing the concentration of C by a factor of 6 will increase the rate by 6^1U1P12=6. The overall increase in the rate will be 4*2*6=48. Therefore, the correct answer is C.

For a Reaction That Follows the General Rate Law Rate