If the concentration of a reactant is 6.25%, how many half-lives has it gone through?

Question

Quizplus · Accepted Answer

To determine the number of half-lives, we need to use the formula:

concentration final = concentration initial x (1/2)^(number of half-lives)

Rearranging the formula, we get:

number of half-lives = log (concentration final / concentration initial) / log (1/2)

Plugging in the values, we get:

number of half-lives = log (0.0625/1) / log (1/2) = 4

Therefore, the answer is D, which corresponds to 4 half-lives.

If the Concentration of a Reactant Is 6