The rate constant for a second-order reaction is 0.54 L mol^-1s^-1. What is the half-life of this reaction if the initial concentration is 0.27 mol L^-1?

Question

Quizplus · Accepted Answer

The half-life of a second-order reaction is given by the equation t_1/2 = 1/(k[A]₀), where k is the rate constant and [A]₀ is the initial concentration. Substituting the given values into this equation, we get t_1/2 = 1/(0.54 L mol^-1s^-1 x 0.27 mol L^-1) = 6.9 s.

The Rate Constant for a Second-Order Reaction Is 0