A reaction with an activation energy of 34.0 kJ mol^-1 has a rate constant of 26.8 s^-1 at 354 K. What is the rate constant at 314 K?

Question

Quizplus · Accepted Answer

The Arrhenius equation can be used to calculate the rate constant at a different temperature:k = Ae^(-Ea/RT)where:k is the rate constantA is the pre-exponential factorEa is the activation energyR is the gas constant (8.314 J mol^-1 K^-1)T is the temperature in KelvinWe can use the given information to solve for A:26.8 s^-1 = Ae^(-34.0 kJ mol^-1 / (8.314 J mol^-1 K^-1 * 354 K))A = 1.00 x 10^7 s^-1Now we can use the Arrhenius equation to calculate the rate constant at 314 K:k = 1.00 x 10^7 s^-1 * e^(-34.0 kJ mol^-1 / (8.314 J mol^-1 K^-1 * 314 K))k = 6.15 s^-1Therefore, the correct answer is A.

A Reaction with an Activation Energy of 34