A 5.00 g sample of liquid water at 25.0 °C is heated by the addition of 145 J of energy. The final temperature of the water is ________ °C. The specific heat capacity of liquid water is

Question

Quizplus · Accepted Answer

We can use the equation Q = mcΔT to solve this problem, where Q is the amount of energy added, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the given values, we get:
145 J = (5.00 g)(4.184 J/g°C)(ΔT)
Solving for ΔT, we get ΔT = 6.93°C. However, we need to find the final temperature, not just the change in temperature. So we add ΔT to the initial temperature of 25.0°C to get the final temperature of 31.9°C. Therefore, the answer is E.

A 500 G Sample of Liquid Water at 25