How many moles of an ideal gas are required to produce a pressure of 3.00 bar in a 1.50 L container with a temperature of 25.0 °C?
A) 0.146 mol
B) 0.0874 mol
C) 0.182 mol
D) 0.914 mol
E) 1.08 mol

Question

Quizplus · Accepted Answer

We can use the ideal gas law equation PV = nRT to solve for the number of moles of gas required.

First, we need to convert the temperature to Kelvin by adding 273.15:

T = 25.0 °C + 273.15 = 298.15 K

Now we can plug in the values:

(3.00 bar) (1.50 L) = n (0.0821 L·atm/mol·K) (298.15 K)

Solving for n gives:

n = (3.00 bar * 1.50 L) / (0.0821 L·atm/mol·K * 298.15 K) = 0.1819 mol

Rounding to three significant figures, we get 0.182 mol, which is answer choice C.

How Many Moles of an Ideal Gas Are Required to Produce