What is the volume of 9.783 × 10²³ atoms of He at 9.25 bar and 512 K? A) 7.48 L B) 3.69 L C) 1.85 L D) 15.4 L E) 30.8 L

Question

Quizplus · Accepted Answer

The ideal gas law can be used to calculate the volume of a gas:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.We are given the number of atoms, not the number of moles. We can use Avogadro's number to convert the number of atoms to the number of moles:n = 9.783 × 10^23 atoms / 6.022 × 10^23 atoms/mol = 1.625 molNow we can plug in the values we know into the ideal gas law:(9.25 bar)(V) = (1.625 mol)(0.0821 Latm/(molK))(512 K)V = 7.48 LTherefore, the volume of 9.783 × 10^23 atoms of He at 9.25 bar and 512 K is 7.48 L.

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