How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.635 bar) according to the following reaction? Assume that there is excess Xe.
Xe(g) + 3F2(g) → XeF6(g)
A) 1.21 × 1023 molecules XeF6
B) 8.25 × 1023 molecules XeF6
C) 2.75 × 1023 molecules XeF6
D) 7.29 × 1023 molecules XeF6
E) 1.37 × 1023 molecules XeF6
Correct Answer:
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