The action of some commercial drain cleaners is based on the following reaction: 2NaOH(s) + 2Al(s) + 6H₂O(l) → 2NaAl(OH) ₄(s) + 3H₂(g)
What is the volume of H₂ gas formed at STP when 6.32 g of Al reacts with excess NaOH?

Question

Quizplus · Accepted Answer

The molar mass of Al is 26.98 g/mol. 6.32 g of Al is 0.234 mol. According to the balanced equation, 2 moles of Al produce 3 moles of H₂. Therefore, 0.234 mol of Al will produce 0.351 mol of H₂. At STP, 1 mole of gas occupies 22.4 L, so 0.351 mol of H₂ will occupy 7.86 L. However, the closest option is 7.98 L.

The Action of Some Commercial Drain Cleaners Is Based on the Following