According to the following balanced reaction, how many moles of KOH will be formed from 5.44 moles of H₂O? Assume an excess of KO. 4KO(s) + 2H₂O(l) → 4KOH(s) + O₂(g) A) 2.72 moles KOH B) 16.7 moles KOH C) 10.9 moles KOH D) 8.33 moles KOH E) 4.87 moles KOH

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Quizplus · Accepted Answer

From the balanced equation, we can see that 2 moles of H₂O react with 4 moles of KOH. This means that 1 mole of H₂O will react with 4/2 = 2 moles of KOH. Therefore, 5.44 moles of H₂O will react with 5.44 x 2/2 = 10.9 moles of KOH. Since there is an excess of KOH, all of the 10.9 moles of KOH will be formed.

According to the Following Balanced Reaction, How Many Moles of KOH