How many SO 3 2- ions are contained in 99.6 mg of Na 2 SO 3 ? The molar mass of Na 2 SO 3 is 126.05 g mol -1 .

A) 1.52 × 10 27 SO 3 2- ions

B) 4.76 × 10 20 SO 3 2- ions

C) 2.10 × 10 21 SO 3 2- ions

D) 1.05 × 10 21 SO 3 2- ions

E) 9.52 × 10 20 SO 3 2- ions

Question

How many SO 3 2- ions are contained in 99.6 mg of Na 2 SO 3 ? The molar mass of Na 2 SO 3 is 126.05 g mol -1 .

A) 1.52 × 10 27 SO 3 2- ions

B) 4.76 × 10 20 SO 3 2- ions

C) 2.10 × 10 21 SO 3 2- ions

D) 1.05 × 10 21 SO 3 2- ions

E) 9.52 × 10 20 SO 3 2- ions

Quizplus · Accepted Answer

Step 1: Calculate the number of moles of NaS1U1B12S1U1B0SOS1U1B13S1U1B0.
- First, convert 99.6 mg to grams: 99.6 mg × (1 g/1000 mg) = 0.0996 g
- Next, divide by the molar mass: 0.0996 g / 126.05 g molS1U1P1-1S1S1P0 = 7.898 × 10S1U1P-4S1S1P0 mol NaS1U1B12S1U1B0SOS1U1B13S1U1B0

Step 2: Convert the moles of NaS1U1B12S1U1B0SOS1U1B13S1U1B0 to moles of SOS1U1B13S1U1B0 ions.
- Since the ratio of NaS1U1B12S1U1B0SOS1U1B13S1U1B0 to SOS1U1B13S1U1B0 ions is 1:1, the number of moles of SOS1U1B13S1U1B0 ions is also 7.898 × 10S1U1P-4S1S1P0.

Step 3: Calculate the number of SOS1U1B13S1U1B0 ions.
- Multiply the number of moles by Avogadro's number: 7.898 × 10S1U1P-4S1S1P0 × 6.022 × 10S1U1P23S1S1P0 ions/mol = 4.76 × 10S1U1P120S1S1P0 ions

Therefore, the answer is B, 4.76 × 10S1U1P120S1S1P0 SOS1U1B13S1U1B0S1U1P12- ions.

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