What is the empirical formula of a compound that is 66.6% C, 11.2% H, and 22.2% O by mass?

Name: What is the empirical formula of a compound that is 66.6% C, 11.2% H, and 22.2% O by mass?
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Quizplus · Accepted Answer

To find the empirical formula, convert the percentages to moles: C: 66.6 g / 12.01 g/mol = 5.55 mol, H: 11.2 g / 1.008 g/mol = 11.11 mol, O: 22.2 g / 16.00 g/mol = 1.39 mol. Divide each by the smallest number of moles (1.39) to get the ratio: C: 4, H: 8, O: 1. The empirical formula is C₄H₈O.

What Is the Empirical Formula of a Compound That Is