How many Fe(II)ions are there in 20.0 g of FeSO₄?

Question

Quizplus · Accepted Answer

To find the number of Fe(II) ions, we need to first calculate the molar mass of FeSO4. 
FeSO4 = Fe + SO4
Fe = 1 × 55.85 = 55.85 g/mol 
SO4 = 1 × 32.06 + 4 × 16.00 = 96.06 g/mol
Total molar mass = 55.85 + 96.06 = 151.91 g/mol

Next, we need to find how many moles of FeSO4 are in 20.0 g:
20.0 g / 151.91 g/mol = 0.1316 mol FeSO4

Since FeSO4 contains one Fe(II) ion per molecule, the number of Fe(II) ions is equal to the number of moles of FeSO4:
0.1316 mol FeSO4 × 6.022 × 10^23 molecules/mol = 7.92 × 10^22 Fe(II) ions

Therefore, the answer is B.

How Many Fe(II)ions Are There in 20