How many moles of Kr are contained in 398 mg of Kr? A) 4.75 × 10^-3 moles Kr B) 33.4 moles Kr C) 2.11 × 10^-4 moles Kr D) 2.99 × 10^-3 moles Kr E) 1.19 × 10^-4 moles Kr

Question

Quizplus · Accepted Answer

To find the number of moles of Kr, you divide the mass of Kr by its molar mass. The molar mass of Kr (Krypton) is approximately 83.798 g/mol. Convert 398 mg to grams (0.398 g), then divide by the molar mass: 0.398 g / 83.798 g/mol = 4.75 × 10^-3 moles Kr.

How Many Moles of Kr Are Contained in 398 Mg