Table 6.2
Observation Number
$$\begin{array} { | c | c | c | c | c | c | }
\hline \begin{array} { c }
\text { Sample } \
\text { Number }
\end{array} & 1 & 2 & 3 & 4 & 5 \
\hline 1 & 10.1 & 10.6 & 9.8 & 9.9 & 10.9 \
2 & 9.7 & 9.5 & 10.3 & 9.9 & 10.5 \
3 & 10.1 & 10.7 & 9.2 & 10.0 & 10.1 \
4 & 9.9 & 9.8 & 10.5 & 10.4 & 10.1 \
5 & 10.4 & 10.1 & 10.9 & 9.9 & 10.3 \
\hline
\end{array}$$
-Using Table 6.2,for the R-chart,what is the value of LCLR?
A) less than or equal to 0.01
B) greater than 0.01 but less than or equal to 0.02
C) greater than 0.02 but less than or equal to 0.03
D) greater than 0.03

Question

Table 6.2
Observation Number
 $$\begin{array} { | c | c | c | c | c | c | } 
\hline \begin{array} { c } 
\text { Sample } \
\text { Number }
\end{array} & 1 & 2 & 3 & 4 & 5 \
\hline 1 & 10.1 & 10.6 & 9.8 & 9.9 & 10.9 \
2 & 9.7 & 9.5 & 10.3 & 9.9 & 10.5 \
3 & 10.1 & 10.7 & 9.2 & 10.0 & 10.1 \
4 & 9.9 & 9.8 & 10.5 & 10.4 & 10.1 \
5 & 10.4 & 10.1 & 10.9 & 9.9 & 10.3 \
\hline
\end{array}$$
-Using Table 6.2,for the R-chart,what is the value of LCLR?
A) less than or equal to 0.01
B) greater than 0.01 but less than or equal to 0.02
C) greater than 0.02 but less than or equal to 0.03
D) greater than 0.03

Quizplus · Accepted Answer

For the R-chart, LCLR = 0 because negative values are not permitted. The formula for LCLR is:

LCLR = D3*Rbar

where D3 is a constant dependent on the sample size, and Rbar is the average range.

For n=5, D3=0, so LCLR=0. Therefore, the answer is A, "less than or equal to 0.01".

Table 62 Observation Number -Using Table 6

Table 62
Observation Number -Using Table 6