Table 9.9
The administration department of a small college is now designing its layout for newly built office space. From statistical samplings over the last three months, the following trip matrix was developed for daily trips between departments.
Trip Matrix (trips/day)
$$\begin{array} { | c | c | c | c | c | c | c | }
\hline & \mathrm { A } & \mathrm { B } & \mathrm { C } & \mathrm { D } & \mathrm { E } & \mathrm { F } \
\hline \mathrm { A } & - & 10 & 75 & & & 140 \
\mathrm {~B} & & - & & & 95 & \
\mathrm { C } & & & - & & 130 & 130 \
\mathrm { D } & & & & - & 10 & \
\mathrm { E } & & & & & - & 95 \
\mathrm {~F} & & & & & & - \
\hline
\end{array}$$
-Use the information in Table 9.9.Which switch of two offices within the department will improve the total load-distance score the most?
A) B and C
B) C and D
C) A and C
D) B and E

Question

Table 9.9
The administration department of a small college is now designing its layout for newly built office space. From statistical samplings over the last three months, the following trip matrix was developed for daily trips between departments.
Trip Matrix (trips/day)
 $$\begin{array} { | c | c | c | c | c | c | c | } 
\hline & \mathrm { A } & \mathrm { B } & \mathrm { C } & \mathrm { D } & \mathrm { E } & \mathrm { F } \
\hline \mathrm { A } & - & 10 & 75 & & & 140 \
\mathrm {~B} & & - & & & 95 & \
\mathrm { C } & & & - & & 130 & 130 \
\mathrm { D } & & & & - & 10 & \
\mathrm { E } & & & & & - & 95 \
\mathrm {~F} & & & & & & - \
\hline
\end{array}$$
-Use the information in Table 9.9.Which switch of two offices within the department will improve the total load-distance score the most?
A) B and C
B) C and D
C) A and C
D) B and E

Quizplus · Accepted Answer

To calculate the total load-distance score, we need to multiply the number of trips between departments with the distance between their locations. Since we are looking for a switch of two offices, we need to consider the change in load and distance for each pair of offices. Switching from C to D would reduce the total load-distance score by (130-10)*distance(C,D) + (130-10)*distance(D,C) = 240*distance(C,D), while switching from B to C would reduce the total load-distance score by (95-75)*distance(B,C) + (130-95)*distance(C,B) = 20*distance(B,C) + 35*distance(C,B). Therefore, switching from B to C would improve the total load-distance score the most.

Table 99 the Administration Department of a Small College Is Now

Table 99
the Administration Department of a Small College Is Now