For the reaction Y→X at standard conditions with [Y] = 1 M and [X] = 1 M, ΔG is initially a large negative number.As the reaction proceeds, [Y] decreases and [X] increases until the system reaches equilibrium.How do the values of ΔG and ΔG° change as the reaction equilibrates?

Question

Quizplus · Accepted Answer

As the reaction proceeds towards equilibrium, the change in free energy (ΔG) decreases because the concentrations of both reactants and products become more similar. However, the standard free energy (ΔG°) remains the same because it is a constant value that represents the free energy change of the reaction under standard conditions. Therefore, the best choice is A, where ΔG becomes less negative (approaching zero) and ΔG° stays the same.

For the Reaction Y→X at Standard Conditions with [Y] =