Find the Maclaurin polynomial of order 2 for

Question

Quizplus · Accepted Answer

The Maclaurin polynomial of order 2 for any function f(x) is given by:
P2(x) = f(0) + f'(0)x + (f''(0)/2!)x^2
In this case, since we don't have a function given, we can assume that the value 11ead0bc_8b84_d9f4_99a0_a5259fb18666_TB6988_11 represents a constant. Therefore, we have:
f(x) = 11ead0bc_8b84_d9f4_99a0_a5259fb18666_TB6988_11
f'(x) = 0
f''(x) = 0
Substituting these values in the formula for P2(x), we get:
P2(x) = 11ead0bc_8b84_d9f4_99a0_a5259fb18666_TB6988_11 + 0*x + 0 = 11ead0bc_8b84_d9f4_99a0_a5259fb18666_TB6988_11
Therefore, the answer is B) 11ead0bc_8b85_0106_99a0_f9835bc0f4b4_TB6988_11.

Find the Maclaurin Polynomial of Order 2 for