Find the force on a 190 ft² horizontal surface 22 ft deep in water. Neglect the effect of the atmosphere above the liquid. (The density of water is 62.4 lb/ft³.) A) 4,180 lb B) 260,832 lb C) 130,416 lb D) 8,346,624 lb E) 9,810 lb

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Quizplus · Accepted Answer

The force on a submerged surface in a fluid can be calculated using the formula: Force = Pressure * Area. The pressure due to the water at a depth can be calculated using the formula: Pressure = density * gravity * depth. Given that the density of water is 62.4 lb/ft^3, and using the standard acceleration due to gravity as 32.2 ft/s^2 (even though it's not explicitly given, this is a common value to use in such calculations), the pressure at a depth of 22 ft is Pressure = 62.4 lb/ft^3 * 32.2 ft/s^2 * 22 ft. However, for this calculation, we only need to consider the density and depth since the question neglects atmospheric pressure and assumes a standard gravitational effect, simplifying the calculation to Pressure = density * depth = 62.4 lb/ft^3 * 22 ft = 1372.8 lb/ft^2. The area of the surface is 190 ft^2 (assuming the "²" is a typographical error and should be disregarded). Therefore, the total force is Force = Pressure * Area = 1372.8 lb/ft^2 * 190 ft^2 = 260,832 lb.

Find the Force on a 190 Ft2 Horizontal Surface 22

Find the Force on a 190 Ft² Horizontal Surface 22