Approximate the area of the region that lies below y = cos x and above y = 0.12x, where 0 $\le$ x $\le$ $\pi$. Approximate area to three decimal places.
A) 0.8679
B) 0.852
C) 1
D) 0.7854
E) 0.8821

Question

Approximate the area of the region that lies below y = cos x and above y = 0.12x, where 0 $\le$  x $\le$   $\pi$. Approximate area to three decimal places.
A) 0.8679
B) 0.852
C) 1
D) 0.7854
E) 0.8821

Quizplus · Accepted Answer

The area is approximated by the integral of cos x - 0.12x from 0 to pi/10. The integral of cos x is sin x and the integral of 0.12x is 0.06x^2. So the area is approximately sin(pi/10) - 0.06(pi/10)^2 = 0.8679 (to three decimal places).

Approximate the Area of the Region That Lies Below Y ≤\le≤

Approximate the Area of the Region That Lies Below Y $\le$