Answer true or false. An object thrown upward reaches a height of s(t) = -9.8t² + 39.2t. The object is highest at t = 2, where t is in seconds?

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Quizplus · Accepted Answer

At the maximum point of the object's height, the velocity is zero. We can find this point by taking the derivative of s(t) and setting it equal to zero: s'(t) = -9.8 + 39.2 = 0. Solving for t, we get t = 4 seconds. Therefore, the statement is false and the object is highest at t = 4.

Answer True or False